How is this implemented? Is it just functions and the language assumes the first parameter is autofilled with variable.function syntax?
from datetime import datetime from dateutil.relativedelta import relativedelta print(datetime.now() + relativedelta(years=10)) # 2035-08-24 12:02:49.795177This is like a 10yo meme template, fellow kids pls update your meme stashes!
Meh. If it works it works. Keep the golden oldies in circulation I say!
🟥🟥🔵👷I guess were doing memes now.
Never worked on Ruby, so I definitely cannot judge it, but that syntax looks so uncomfortable…
And the best part is the Ruby way accounts for leap years.
I prefer the one on the left because it’s evident it doesn’t account for leap days, while I’d be questioning whether the one on the right does.
I’ll give it a shot. Looks a bit kludgy and I’ve been typing this on my phone while sitting on the toilet. What am I doing with my life?
from datetime import datetime now = datetime.now() year = now.strftime('%Y') month = now.strftime('%m') day = now.strftime('%d') tenyearsago = datetime(year-10, month, day) print(tenyearsago.strftime('%d.%m.%Y')or just this
from datetime import datetime today = datetime.today() ten_years_ago = today.replace(year=today.year - 10) print("Date 10 years ago:", ten_years_ago.date())
