i wonder if the us did the same in kuwait? assuming this is true, of course.

im having a hard time copying what i wrote above cuz im on jerboa mobile, but the kernel version from uname does indeed match the directory in which its looking (see above)

yeah, i’ve built an iso using archiso (https://wiki.archlinux.org/title/Archiso, https://github.com/archlinux/archiso). i’m running the 2 modprobe commands while booted into that iso (the live environment).

i have the following packages installed on the live iso when building that image:

• arch-install-scripts
• base
• base-devel
• bind
• btrfs-progs
• cryptsetup
• dosfstools
• dracut
• edk2-shell
• efibootmgr
• git
• gptfdisk
• inetutils
• libfido2
• linux-firmware
• linux-zen
• linux-zen-headers
• lvm2
• man
• memtest86+
• memtest86±efi
• net-tools
• parted
• thin-provisioning-tools
• usbutils
• util-linux
• vim
• wge

my next steps would normally be

cryptsetup -v luksFormat /dev/vda2

which asks for a passphrase, creates a key in slot 0, and seems to succeed in encrypting the partition.

cryptsetup luksOpen /dev/vda2 map-root

this asks for the passphrase to unlock, but gives the following response:

device-mapper: reload ioctl on map-root (253:0) failed: Invalid argument

and then my formatting step

mkfs.btrfs -f -L "fs-root-btrfs" /dev/mapper/map-root

clearly doesn’t work.

“pacman -Q cryptsetup” yields “cryptsetup 2.8.6-1”

“uname -a” yields

Linux larch.domain.net 7.1.3-zen1-2-zen #1 ZEN SMP PREEMPT_DYNAMIC Thu, 09 Jul 2026 20:39:38 +0000 x86_64 GNU/Linux

i initially tried this on my laptop, bc i didn’t expect any trouble. but i’m working with a libvirt virtual machine now until i figure out the issue.

i think if you ask that question, itll result in abolishing the minimum wage, in the usa anyway

does stapler really mean forklift, and lager really mean storage, in german?

basically youre asking the ai to generate chunks, then check those chunks. it might work

edit: sorry i didnt provide a soln

When I use just the wget aspect of the command, it dumps a bunch of jargon to my terminal, so I think that means I have the “stdout” aspect of that command right.